C-Program For Addition_Of_Digits_Number

C-Code to sum the digits of a number

#include<stdio.h>
#include<conio.h>
void main()
{
  int n,sum=0,i;
  printf("Enter the number: ");
  scanf("%d",&n);
  while(n)
  {
      i=num%10;
      num=num/10;
      sum=sum+i;
  }
  printf("Sum of digits of %d is %d",n,sum);
  getch();
}

Output:
Enter the number: 567
Sum of digits of 567 is 18

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Sum of digits of a number

#include<stdio.h>

#include<conio.h>

void main()

{

  int n,sum=0,i;

  printf("Enter the number: ");

  scanf("%d",&n);

  for(;n!=0;n=n/10)

 {

      i=n%10;

      sum=sum+i;

  }

  printf("Sum of digits of  %d is %d",n,sum);

  getch();

}

Output:

Enter a number: 567

Sum of digits of number:  18

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Addition of digits of a number to a single digit

#include<stdio.h>

#include<conio.h>

void main()

{

int n,sum,d;

sum=0;

printf("Enter the number: ");

scanf("%d",n);

while((n>9) || (n==10))

{

while(n>0)

{

d=n%10;

n=n/10;

s=s+d;

}

n=sum;

}

printf("Sum of digits to a single number of a given number %d is %d",n,sum);

getch();

}

Output:

Enter the number: 567

Sum of digits to a single number of a given number 567 is 9